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Jack's Chemistry Revision Notes

or...

Why you'd have to be mad to study chemistry


VERSION 0.2.0 - 16 MAY 1999


Atomic Structure (1.1)


A - mass number

Z - number of protons


Mass spectrometer [1]

Vaporised sample is ionised, accelerated by an electric field, deflected by a magnet and made to hit a detector.


Order of electron shells [2]


1s 2s 2p 3s 3p 4s 3d 4p


[Ar] = 1s2 2s2 2p6 3s2 3p6


Ionisation energy across period 2 [3]

1. Shielding by existing electron orbitals causes this.

eg. Boron shielded by whole 2s orbital.


                      2. Pair effects

                      Nitrogen has 3 unpaired p electrons.

Oxygen has 2 unpaired p electrons, and a pair. It is easier to remove one of the p electrons from oxygen than from nitrogen, because there are less unpaired electrons.



Amount of Substance (1.2)

Misc [4]


Avogadro Constant = 6.0 x 1023 per mole


Ar = relative atomic mass

Mr = relative molecular mass

Mr is measured relative to Carbon 12.


Ideal Gas Equation [5]


pV = nRT


(R = 8.31JK-1mol-1)



Bonding (1.3)



Bond types [6]


Co-ordinate: A covalent bond where both electrons are from the same atom.

Metallic: lattice of +ve ions surrounded by delocalised electrons.


Pauling's scale of electronegativity [7]


Scale from 0.7 to 4.0.

electronegativity is the power of an atom to withdraw e- density from a covalent bond

Covalent bonds are not always symmetrical: they may be polarised:


eg. NaCl is truly ionic, MgCl2 has some covalent character, and AlCl3 and SiCl4 are covalent.


Intermolecular bonds: Hydrogen bonding [8]


(lone pair(s) and high electronegativity required for the O atom)


This is why water has an oddly high boiling pt.

(H2S = -50OC, H2Se = -30OC, but H2O = 100OC)


H-bonds are very strong (less than covalent bonds though) and are called permanent bonds.


NH3 can make 1 hydrogen bond, HF can make 3.


How it works: electrons on the H are pulled away by the high electronegativity of the other atom, leaving an exposed side of the proton, which attracts negative areas on other molecules, eg. Lone pairs.


Intermolecular bonds: Dipole-dipole attraction [9]


weaker than H-bonding:-


dipole-dipole attraction between O and C where the dipole is.









Intermolecular bonds: Van der Waals forces [10]

Non-polar molecules do have I/M forces, they are the induced dipole-dipole type.

e- movement induces a dipole in a molecule. These forces are attracting and breaking all the time.


Bond Rules

All things have Van der Waals I/M forces. If a molecule has a difference in electronegativity across it (i.e. A dipole) then there will also be dipole-dipole attraction. And if one of the atoms has very high electronegativity and lone pairs (N, O, F), and is bonded to a hydrogen atom, then hydrogen bonding will also exist.


Types of crystal [11]





Repulsion rule [12]


A lone pair of electrons produces a greater repulsion effect than a bonding pair.


lone pair - lone pair repulsion > lone pair - bonding pair repulsion > bonding pair - bonding pair repulsion


Periodicity (1.5)







Patterns in period 3 [17]


Period #3 is a bit like period #2.


- For metals, melting point increases as the charge/size ratio increases - better metallic bonding.

- Silicon is macromolecular, so it has very strong bonds. (covalent bonds linking all atoms together)

- The final elements are simple molecular: with weak Van der Waals I/M forces.

(increasing nuclear charge => electrons attracted more strongly)



Extra Solid Types

PCl5 actually exists as an ionic solid consisting of PCl4+ and PCl6 -. AlCl3 is a solid dimer at room temperature.


Patterns down group 1 [18]


Group I metals react with water to form metal hydroxides and hydrogen:

2Na + 2H2O -> H2 + 2NaOH


Metal oxides and chlorides [19]


MgO, SO2, MgCl2, and AlCl3 can be formed by direct combination (burning).


Reactions of oxides of period 3 elements with water [20]


Basic element

Na2O

Dissolves slowly to form strong alkali

MgO

Dissolves slowly to form weak alkali

Amphoteric element

Al2O3

Does not react

Acidic element

SiO2

Does not react

P4O10

Forms phosphoric acid soln.

SO2

Forms sulphuric acid soln.

SO3

Forms sulphuric acid soln.


So, the metals form alkalis, and the non-metals/metalloids either form acids or do not react.


Reactions of chlorides of period 3 elements with water [21]


NaCl

Dissolve easily, solution pretty neutral

MgCl2

Al2Cl6

Reacts vigorously with water, produces HCl fumes

Solution acidic, pH 2 or 3.

SiCl4

PCl5


Additional Notes on periodicity [22]


In each period the oxides of the metals and metalloids have giant structures, whereas the oxides of non-metals are composed of simple molecules.



From left to right, the oxides of all these molecules change from being ionic, involatile, and metallic, through being giant molecular, involatile and amphoteric, to being simple molecular, volatile, and acidic.


Lithium (thermal stability of compounds) [23]





The Halogens (2.4)


[40]

Most electronegative: Fluorine

Highest boiling point: Astatine

Best oxidising agent: Fluorine

Best reducing agent: Astatide ions

(I/M forces are just Van der Waals)


Products of reactions between NaX and Sulphuric Acid [41]

(where X is a halogen): NaX + H2SO4(conc)


Halide ions can reduce sulphur in H2SO4 by varying degrees. In H2SO4 the S has oxidation state +6. Iodide ions are able to reduce this to +4 (SO2), 0 (S) and -2 (H2S).

reagent

product

NaF

HF

NaCl

HCl

NaBr

HBr and a little Br2 and SO2

NaI

I2 and a little HI and S, H2S, SO2

NaBr and NaI are oxidised in the reaction, but HF and HCl cannot be oxidised by the acid.


Br2 is a brown gas. I2 is a purple gas, and a black precipitate.


Reactions of Cl


[42] ..with water: chlorine + water -> hydrochloric acid + hypochlorous acid

Cl2 + H2O -> H+(aq) + Cl-(aq) + HClO(aq)


Cl is simultaneously reduced and oxidised - a disproportionation.

The product is also known as chlorine water. It is used to make bleach and treat water, and kills germs.


[43] ..with NaOH

This reaction depends on concentration and temperature.

At room temperature and using dilute NaOH:


Cl2 + 2OH- -> Cl-(aq) + ClO-(aq) + H2O(aq)


Forms Sodium Hypochlorite which is a bleach.


Testing for halides [44]

Silver nitrate (AgNO3) can be used to detect halide ions.


halide ion + silver nitrate -> nitrate ion + silver halide

or, for reaction with X- (halide)

X- + Ag+ + NO3- -> NO3- + AgX(s)


X can be identified from the colour of the silver halide AgX: [45]

AgI(s) is yellow

AgBr(s) is creamy colour

AgCl(s) is white


X can also be identified by dissolving the silver halide in ammonium hydroxide: [46]

AgI(s) doesn't dissolve

AgBr(s) partially dissolves

AgCl(s) dissolves fully



Kinetics (3.1)






Maxwell-Boltzmann Distribution [47]

DrawObj

increasing T shifts to right


Area under curve is total number of particles





Reaction rate [48]


Rate = Damount / Dtime or Dconcentration / Dtime


The rate is affected by:

  1. state of division (i.e. The surface area, powdered form is faster)

  2. temperature (more energy -> more collisions have required Ea)

    (a small increase in T may lead to a large increase in rate)

  3. concentration (increased P(collision))

  4. catalyst (provides alternate route with lower Ea)


Rate equation [50]


Rate = k [A]m[B]n


m and n are the orders of the reaction with respect to reagents A and B.

k is the rate constant.


Thermodynamics & Energetics (4.1 1.4)



Enthalpy [74]


Definition: Enthalpy (H) is the energy content at constant pressure.

Standard enthalpy changes (DHQ) refer to standard conditions: 1 atm, 298K, 1M


Types of Enthalpy [75]


+ve means that energy goes from surroundings to system (i.e. Endothermic)

Ionisation enthalpy

One mole of e- from gaseous atoms

DHQI 1

+ve

Electron affinity

One mole of e- added to gaseous atoms

DHQe 1

-ve

Lattice dissociation enthalpy

Ionic solid dissociating to gaseous atoms

DHQlatt

+ve

Solution enthalpy

One mole of ionic solid dissolving in water to make aqueous ions

DHQsoln

+ve

Enthalpy of hydration

1 mole Gaseous ions forming aqueous ions

DHQhyd

-ve

Enthalpy of combustion

Buring 1 mole of reagents in standard states

DHQc

-ve

Enthalpy of formation

Forming 1 mole of something in standard state from elements in standard states

DHQf


Enthalpy of sublimation

Making 1 mole of gaseous atoms

DHQsub

+ve

Enthalpy of atomisation

Often the same as sublimation.

DHQdiss

+ve


Hess's Law [14]


Total Denthalpy is independent of the reaction route taken.



Bond Enthalpy [76]

Bond Enthalpy is the definite amount of energy associated with each chemical bond. Bond enthalpies can be used to predict whether or not, and how easily two substances will react.


bond breaking - endothermic

bond making - exothermic


example: all the bonds in CH4 are identical C-H bonds with the same bond enthalpy, E(C-H). To break all four, 4E(C-H) is required.


DH ( CH4(g) -> C(g) + 4H(g) ) = 4E(C-H)


Generally, the lower the bond enthalpy, the weaker the bond.


When heat or light can break bonds, it will usually break the weakest (lower bond enthalpy) first.


eg. Cracking works because C-C bonds are weaker than H-C bonds (C-C bonds split homolytically to form radicals).

eg. H2 + Cl2 works because Cl-Cl bonds split in the presence of light. (initiation, propagation, termination steps..)



Molecule shapes [16]



Linear

180


V-shaped

105


Tetrahedral

109.5


Pyramidal

107


Planar

120


Both tetrahedral

109.5


Trigonal bipyramidal

90 and 120


Octahedral

90



Spontaneous reactions [78]


DH, whilst important, is not sufficient to explain spontaneous change.

=> spontaneous exothermic change (eg. burning) makes sense in terms of DH but spontaneous endothermic change does not.


Entropy (S) [79]


UNITS: JK-1mol-1 (NOT kJ)


Positive DS for a reaction indicates that the reaction is feasible (ie. spontaneous).


S rules of thumb [80]



2nd law of thermodynamics [81]


DStotal = DSsystem + DSsurroundings

DStotal must be positive because overall entropy is always increasing.


And because DSsystem = DSSproducts - DSSreactants

and DSsurroundings = - DH / T


the feasibility of a reaction can be determined by calculating the DSsystem and DSsurroundings from databook values. If DStotal is positive, the reaction is feasible at that temperature. Thus the feasibility of a reaction depends on the balance between entropy and enthalpy. [82]


Gibbs free energy change [83]


DG = DHsystem - TDSsystem


For a feasible reaction DG must be zero or negative, note this is the opposite way round to DS.



Equilibria (4.2 2.1)


Many reactions are reversible. At equilibrium, both forward and reverse reactions are proceeding. For a homogenous system in equilibrium, where: A + B <-> C + D,


Kc = Right / Left = [C]eq[D]eq / [A]eq[B]eq


[25] Le Chatelier's principle: The system resists change.

=> Increase conc. of something, it reduces it.



But Kc depends on temperature. The effect of T can be clearly defined:


DG = - RT ln K




Partial pressure and Kp [85]

=> partial pressure is analogous to concentration


The partial pressure of a gas in a gas mixture is the pressure that would be exerted if that gas alone filled the whole volume occupied by the mixture (Dalton's law)


partial pressure PA = Ptotal x mole fraction

(PA of oxygen in air is 0.2 atm, as this is 1/5 of 1 atm (4 parts nitrogen, 1 part oxygen))


Kp is the equilibrium constant for a gas system:

Kp = Right / Left = P(C)eqP(D)eq / P(A)eqP(B)eq


Note that changing pressure of the system does not affect KP, but changing temperature does affect KP.



Contact Process [26]


Haber Process [27]



Acid-Base Equilibria (4.3 2.2)

Bronsted-Lowry: acid is a proton donor, base is a proton acceptor

In any acid-base reaction a proton is transferred.


pH [30]


pH = - log [H+] (H+ in moldm-3)


Dissociation of water [31]


Water is very weakly dissociated: Kc = [H+][OH-] / [H2O]

The ionic product of water, Kw = [H+][OH-]

At 25OC only, Kw = 10-14 mol2dm-3.


pH of a strong base found by finding [H+]: Kw = [H+] x [OH-].



>>> Dissociations are always written with ions on the right.

Therefore, as Kc = right / left, Ka, Kc etc are always ions / molecules.


- Ions Right -


Monoprotic weak acids


A weak acid is only partially dissociated: HA <-> H+(aq) + A-(aq)

The dissociation constant, Ka, is found by:

Ka = [H+(aq)][A-(aq)] / [HA]


The higher the value of Ka, the stronger the acid.


Diprotic weak acids

These are like monoprotic weak acids, except they dissociate twice, producing 2H+.

One example is H2S(aq):

H2S <-> HS-(aq) + H+(aq)

HS-(aq) <-> S2-(aq) + H+(aq)


There are two values of Ka, Ka1, and Ka2:-


Ka1 = [HS-][H+] / [H2S]

Ka2 = [S2-][H+] / [HS-]


Ka2 is always much less than Ka1.


Finding Ka

Ka may be found by this approximation, as [H+] Z [HA-], and [H+] Z 0. (as very few H+ come from the water that the acid is in)


Ka Z [H+]2 / [HA]


Finding pH

and so, if [HA] and Ka are known for a weak acid, it's pH can be calculated:


[H+] Z ( [HA] x Ka )

=> pH Z -log10 ( [HA] x Ka )


pKa

pKa is a pH-like scale for Ka.

pKa = -log10 Ka


pH and pKa

You can combine the above two equations to make:

pH Z ½pKa - ½log [HA]


Weak bases

Just as Ka = [H+][A-] / [HA] for weak acids,

Kb = [B+][OH-] / [BOH] for weak bases.

Kb Z [OH-]2 / [BOH]


pH Z ½pKa + ½pKw + ½log [BOH]



pH Curves


All acid/base titrations produce a pH graph like the one on the left. (a mirror image for an acid added to an alkali)


The endpoint is where the titration should finish: where equal amounts of acid and base have reacted.

Also known as the equivalence point where acid and base are equivalent.



Indicators change colour within a narrow pH range. The right indicator has to be used to show when the titration reaches the endpoint. This isn't always pH = 7 though.


For a strong acid and strong alkali, endpoint is about pH 7.

For a weak acid and strong alkali, endpoint is greater than pH 7.

For a strong acid and weak alkali, endpoint is less than pH 7.

For a weak acid and weak alkali, endpoint is about pH 7.


The indicator should show when the mixture is close to the endpoint.


indicator

Changes between...

Methyl Orange

3 and 4.6

Phenolphthalein

8 and 10


Buffers



Acid buffer: If H+ ions are added, they will react with the ethanoate ions from the salt (because there are more of them than ethanoate ions from the partially dissociated acid). Undissociated ethanoic acid will form. If OH- ions are added, they will combine with the H+ ions to form water, and more of the acid will dissociate.


Alkaline buffer: same sort of mechanism


Uses of buffers



Redox Titration Facts


MnO4 reduces to Mn2+

Cr2O7 2- reduces to 2Cr3+



Redox Equilibria (4.4)


The anode is where the oxidation reaction occurs.


Usually, electrodes are a sample of a metal in a solution of the same metal ions. If M = Zn and soln is ZnSO4(aq):


Zn(s) | ZnSO4(aq)

or

Zn(s) | Zn 2+(aq)


both describe this electrode.




Gas electrode


Sometimes a gas electrode must be used. Here the gas under test is bubbled over a platinum electrode in a solution of ions of the same element as the gas. eg. The standard hydrogen electrode is described as:


Pt (s) | H2(g) | H+(aq)


Standard


The standard for half cells is that everything happens under standard conditions (1 atm for gases, 298K, and 1M solutions).


Redox electrodes


This is where something in solution is either oxidised or reduced, but remains in solution. eg.

Pt (s) | Fe2+(aq) Fe3+(aq)


-> a solution containing 1M iron (II) and 1M iron (III) ions. e- produced by oxidation of Fe2+ or lost by reduction of Fe3+ enter or leave the solution by the Pt electrode.


Cell reactions - standard layout


Zn(s) | ZnSO4(aq) || CuSO4(aq) | Cu(s)



The oxidation cell is put on the left. The overall reaction where oxidation of the left cell occurs is feasible if the left cell potential is less than the right cell potential.


Word Association

Oxidation occurs at the Anode on the Left which is Negative


POSITIVE POTENTIALS OXIDISE OTHERS


ie. the best oxidising agents have the highest E values.


Standard Cell Potential


Standard cell potential, EQ is measured with the Standard Hydrogen Electrode (SHE) as the left hand electrode, and standard conditions. Cells with high E values are the best oxidising agents: they accept e- easily.


Calculating E


Ecell = Eright - Eleft


Ecell is usually calculated by putting the most positive cell on the right.


Secondary standard

A calomel electrode with an EQ value of +0.27V is often used in place of the SHE.


POSITIVE POTENTIALS OXIDISE OTHERS


Principles of Catalytic Action (4.5)


Heterogeneous catalytic action


A heterogeneous catalyst is in a different state to the reagents. One (or more) of the reagents is adsorbed onto the catalyst surface, making it more likely to react with the others. For example, it may become more accessible to collisions, or be held in a particularly active configuration, or be broken into more reactive fragments.


The strength of adsorption is very important. Tungsten adsorbs too well. Silver adsorbs poorly. So Ni and Pt are more commonly used.


A support medium minimises the amount of catalyst while maximising the catalyst surface area.


Homogenous catalytic action


The reaction goes through an intermediate species. If a transition metal catalyst is used, it's oxidation state changes.


Specificity


Catalysts are often highly specific. Enzymes will work for only one reaction. Acid/base catalysts (eg. Acid used to catalyse hydrolysis of an ester) are much more general.


Some Catalysts [35]


Transition metals often make good catalysts (change in oxidation state)

Iron -> Haber process

MnO2 -> decomposition of H2O2

Ni -> margarine (hydrogenation of vegetable oil)



Extraction of Metals (5.1)


Extraction of metals usually involves reduction of a metal oxide. There are several reduction methods: the one used depends on the cost of the reductant, the energy requirements, and the purity of the metal required.


Reduction of metal oxides with carbon

eg. production of iron.


  1. Iron oxide is first heated with coke (mostly carbon) in a sintering plant.

  2. Poured into a blast furnace along with more coke.

  3. The carbon reduces the iron oxide to iron:

2Fe2O3 + 3C -> 4Fe + 3CO2

and also, CO produced by incomplete combustion of coke:

Fe2O3 + 3CO -> 2Fe + 3CO2

  1. The impurities (slag) float on top of the liquid iron poured out of the blast furnace.

Waste gases are used to heat the furnace.


Iron can be further purified by:


Carbon reduction is not perfect for all metals, as with some others carbides are formed.


Reduction of metal oxide with an active metal


Mainly used for chromium and in Thermite process. Advantages:


Sort of substitution of one metal for another:

eg. Cr2O3(s) + 2Al(s) -> 2Cr(s) + Al2O3(s)


Reduction of metal oxide by electrolysis

Used for aluminium extraction because Al2O3 is too stable for carbon reduction: the temp would have to be very high. The bauxite is dissolved in molten cryolite (Na3.AlF6) to lower it's melting point from 2000OC to 950OC. Carbon electrodes are used.


Cathode: Al reduced from Al3+ to Al

Anode: Oxide ions oxidised to oxygen


This is a continuous process using much electricity. Cryolite is damaging to the environment.


Reduction of a metal halide by another metal


Used for production of Ti, which is brittle unless very pure. This process produces very pure metal in quantity. Main Ti ore: TiO2.


TiO2 reacted with C and Cl at 900OC to form TiCl4:

TiO2 + 2C + 2Cl2 -> TiCl4(l) + 2CO


TiCl4 is a dangerous product, it hydrolyses easily and forms HCl fumes in moist air.


It is reacted with Na: (at 550OC)

TiCl4(l) + 4Na(s) -> 4NaCl + Ti(s)


This is also a dangerous reaction as it's highly exothermic. (temp rises to 1000OC) The temperatures are so high that the reaction must happen in an inert atmosphere of argon so that titanium oxides are not formed again. It's all very expensive.


additional: H2 can be used as a reducing agent for metals: no carbides are formed.


Transition Metals (5.2 2.3)



General Properties [34]


  1. coloured compounds

  2. variable oxidation state

  3. form complex ions

  4. show catalytic activity